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[as] Sort op data

Our algorithm is based in that all the occurrences of the same
verbs are consecutive in the instruction array, so if we don't
sort them based in the first key then the algorith will fail.

--- a/as/target/amd64/target.mk

+++ b/as/target/amd64/target.mk

@@ -7,8 +7,8 @@

 	set -e ;\

 	rm -f $@;\

 	trap "rm -f $$$$.c" 0 2 3; \

+	sort -k1 target/x86/x86.dat | \

 	awk -v cpu=BITS64 -v family=x86 \

-		-f target/gen.awk  \

-		< target/x86/x86.dat > $$$$.c && mv $$$$.c $@

+		-f target/gen.awk  > $$$$.c && mv $$$$.c $@

 OBJ-amd64 = $(OBJ) $(AMD64_LST)

--- a/as/target/i386/target.mk

+++ b/as/target/i386/target.mk

@@ -7,8 +7,8 @@

 	set -e ;\

 	rm -f $@;\

 	trap "rm -f $$$$.c" 0 2 3; \

+	sort -k1 target/x86/x86.dat | \

 	awk -v cpu=BITS32 -v family=x86 \

-		-f target/gen.awk  \

-		< target/x86/x86.dat > $$$$.c && mv $$$$.c $@

+		-f target/gen.awk > $$$$.c && mv $$$$.c $@

 OBJ-i386 = $(OBJ) $(I386_LST)

--- a/as/target/z80/target.mk

+++ b/as/target/z80/target.mk

@@ -7,8 +7,8 @@

 	set -e ;\

 	rm -f $@;\

 	trap "rm -f $$$$.c" 0 2 3; \

+	sort -k1 target/x80/x80.dat | \

 	awk -v cpu=Z80 -v family=x80 \

-		-f target/gen.awk  \

-		< target/x80/x80.dat > $$$$.c && mv $$$$.c $@

-

+		-f target/gen.awk  > $$$$.c && mv $$$$.c $@

+ 

 OBJ-z80 = $(OBJ) $(Z80_LST)