ref: e54af86927ced66fb7fa8ad744cfb609390f04d8
dir: /lib/thread/mutex+futex.myr/
use "atomic" use "futex" pkg thread = type mutex = struct _state : ftxtag ;; const mkmtx : (-> mutex) const mtxlock : (mtx : mutex# -> void) const mtxtrylock : (mtx : mutex# -> bool) const mtxunlock : (mtx : mutex# -> void) pkglocal const mtxcontended : (mtx : mutex# -> void) ;; const Unlocked = 0 const Locked = 1 const Contended = 2 var nspin = 10 /* FIXME: pick a sane number, based on CPU count */ const mkmtx = { -> [._state = Unlocked] } const mtxlock = {mtx var c /* Uncontended case: we get an unlocked mutex, and we lock it. */ c = Locked for var i = 0; i < nspin; i++ c = xcas(&mtx._state, Unlocked, Locked) if c == Unlocked -> void ;; ;; /* Contended case: we set the lock state to Contended. This indicates that the lock is locked, and we potentially have threads waiting on it, which means that we will need to wake them up. */ if c == Locked c = xchg(&mtx._state, Contended) ;; while c != Unlocked ftxwait(&mtx._state, Contended, -1) c = xchg(&mtx._state, Contended) ;; } const mtxtrylock = {mtx -> xcas(&mtx._state, Unlocked, Locked) == Unlocked } const mtxunlock = {mtx /* Either the lock is contended or it's uncontended. Any other state is a bug. Uncontended case: If the mutex state is not contended, and we still are uncontended by the xchg() call, then it's safe to simply return; nobody was waiting for us. */ if xchg(&mtx._state, Unlocked) == Contended ftxwake(&mtx._state) ;; } const mtxcontended = {mtx while xchg(&mtx._state, Contended) != Unlocked ftxwait(&mtx._state, Contended, -1) ;; }